45^2+28^2=c^2

Solution for 45^2+28^2=c^2 equation:

45^2+28^2=c^2

We move all terms to the left:

45^2+28^2-(c^2)=0

We add all the numbers together, and all the variables

-1c^2+2809=0

a = -1; b = 0; c = +2809;
Δ = b2-4ac
Δ = 02-4·(-1)·2809
Δ = 11236
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{11236}=106$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-106}{2*-1}=\frac{-106}{-2}
=+53
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+106}{2*-1}=\frac{106}{-2}
=-53
$